Which of the following is considered as an anticancer species?
- A$cis-[Pt(NH_3)_2Cl_2]$
- B$trans-[Pt(NH_3)_2Cl_2]$
- C$[PtCl_3(C_2H_4)]^-$
- D$[PtCl_4]^{2-}$
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Similar Questions
Match the metal in column $I$ with the coordination compounds/enzymes in column $II$.
Column $I$ (Metals) Column $II$ (Coordination compounds) $a. Co$ $i. \text{Wilkinson catalyst}$ $b. Zn$ $ii. \text{Chlorophyll}$ $c. Rh$ $iii. \text{Vitamin } B_{12}$ $d. Mg$ $iv. \text{Carbonic anhydrase}$
| Column $I$ (Metals) | Column $II$ (Coordination compounds) |
| $a. Co$ | $i. \text{Wilkinson catalyst}$ |
| $b. Zn$ | $ii. \text{Chlorophyll}$ |
| $c. Rh$ | $iii. \text{Vitamin } B_{12}$ |
| $d. Mg$ | $iv. \text{Carbonic anhydrase}$ |
DifficultJEE MAIN 2019
View Solution$A$ solution of $FeCl_3$ when treated with $K_4[Fe(CN)_6]$ gives a Prussian blue precipitate due to the formation of:
$A$ blood red colour is obtained when ferric chloride solution reacts with
Easy
View SolutionPrussian blue is due to the formation of
Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$K_3[Fe(CN)_6] + FeCl_3 \longrightarrow Fe[Fe(CN)_6] \downarrow$
$K_3[Fe(CN)_6] + FeCl_3 \longrightarrow Fe[Fe(CN)_6] \downarrow$
Medium
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